Contact Injector (A2080) Manual

©2014-2017, Kevan Hashemi,alignment.hep.brandeis.edu

Contents

Description
Design
Operation
Development
MAY-14JUN-14JUL-14AUG-14
OCT-15DEC-15MAR-16JUN-16
JUL-16OCT-16DEC-16
2017
JAN-17FEB-17MAR-17APR-17

Description

The Contact Injector (A2080) is a LWDAQ device that provides one or more light sources coupled into optical fibers by contact injection. The circuit is designed to work any type of LED (light emitting diode). It can provide LED drive voltage of up to 4.2 V and drive current up to 1.0 A. The A2080A provides 36 separate, individually-fused buck converters to power 36 deep-red Luxeon Z LEDs. Only one LED can be driven at full power at a time, as determined by a single LWDAQ command transmitted to the device. But all LEDs can be driven at 2.5% power at the same time.


Figure: Thirty-Six Way Contact Injector.

The A2080 uses buck converters to convert the LWDAQ ±15 V power supply into an LED drive power supply. The LED drive voltage is equal to the forward voltage drop of the selected LED plus a small voltage across a 0.1-Ω current sensing resistor. Blue and white LEDs have a forward voltage drop of around 3.2 V. At a forward current of 1000 mA, the drive voltage will be around 3.3 V. The A2080A is equipped with deep-red LXZ1-PA01 LEDs. At 800 mA, their forward voltage drop is around 2.1 V. The buck converter provides 800 mA to the LEDs at a cost of 85 mA from the ±15 V power supplies, for an total conversion efficiency of 65%.

VersionDescription
2080A36-Way Injector with Deep-Red Luxeon Z LEDs.
Table 1: Versions of the Contact Injector (A2080).

The A2080 is designed for use in the New Small Wheel of the ATLAS detector at CERN. The circuit and its buck converters will continue to operate efficiently with up to 1 kGy of ionizing radiation, 10×1012 1-Mev eq. n/cm2 neutron radiation, and in the presence of a 0.6-Tesla magnetic field. The contact injection takes place with zirconia ferrule, which presents the polished end of an optical fiber to the 1-mm square LED at a range of 0.2-0.7 mm.


Figure: Thirty-Six Way Contact Injector with Fiber Mounting Plate. Four fibers with custom ferrule are held in place with a single locking piece. For three-dimensional view see here.

The mounting plate serves also as a heat sink for the LEDs as they dissipate up to 2 W with 1000 mA passing through them. A 62-μm diamter fiber with numerical aperture 0.2 placed 1-mm above a deep-red Luxeion Z LED carrying 900 mA will capture 40-50 μm of red light.

Design

A2080A.ods Bill of Materials and Pick and Place Coordinates.
S2080_1.gif: LWDAQ Interface.
S2080_2.gif: Logic and Decoupling.
S2080_3.gif: Buck Converters.
Code: Firmware and test programs for A2080.
A208001D.zip: Thirty-Six Way Injector PCB Gerber Files.
A208001D.pdf: Thirty-Six Way Injector PCB Multi-Layer View.
A2080A_Drawing.pdf: Drawing of A2080A showing dimensions.
A2080A_View.pdf: Three-Dimensional View of A2080A.
A208001A.zip: Prototype Buck Converter PCB, Version A.
A208001B.zip: Prototype Buck Converter PCB, Version B.
A208001C.zip: Prototype Buck Converter PCB, Version C.
S2080X_1.gif: Prototype buck converter.
S208002A.gif: Luxeon Z LED Array.
Ferrule for Contact Injection: Ferrule that presents optical fiber to LED on the injector.
Ferrule for Light Source: Ferrule that acts as light source.

Operation

[01-MAR-17] The P2080A03 firmware provides power levels zero to ten and single-LED control. We turn on LED number n to power level p by sending command n8p, where n is a two-digit hex value specifying the LED and p is the power level. Here are some example commands.

Command
(Hex)
LED Number Power Level
0000 None 0
0080 None 0
010A 1 Undefined
018A 1 10
0A88 10 8
2487 36 7
1784 23 4
2885 None 5
Table: Effect of Command Words on A2080A with P2080A03 Firmware. The undefined states are ones we still have to investigate.

The Flash_All Toolmaker script will use the Diagnostic Instrument to flash all the LEDS on an injector one after the other.

Development

MAY-14

[09-MAY-14] To make a buck regulator in the ATLAS cavern, we must use an air-core inductor. To reduce stray fields from our inductor, we must make it a toroid. We wind our own toroid with 28 AGW wire, 430 μm in diameter. Its resistance is 0.4 Ω. The photograph below shows our breadboard buck regulator with the coil beside it.


Figure: Buck Regulator Breadboard. Note the hand-wound 9-μH toroidal power inductor and the 5-Ω power resistor acting as a load. A bench-top power supply provides the input voltage up to 24 V.

Our inductor coils are square in cross section. If h is the height of the toroid, r1 is its inner radius and r2 is its outer radius, Ampere's Law followed by Faraday's Law and some integration give us the following formula for the toroid inductance in a medium with permeability μ.

L = N2μ h Ln(r1/r2) / 2π

Where N is the number of turns and L is the inductance. We have r1 = 12.5 mm, r2 = 27.5 mm, h = 32 mm, and N = 37, so we expect L = 7 μH. We place a 1.0 kΩ resistor in series with our coil and a capacitor, C, in parallel. We apply a sinusoidal voltage to the resistor and observe the gain and phase of the voltage on the coil with respect to the input. At resonance, the phase is zero. For C = 10 nF resonance is at 520 kHz with gain 0.25. For C = 1.0 nF it is at 1.6 MHz with gain 0.90. For C = 0.0 nF it is at 10.7 MHz with gain 0.95. These three measurements are consistent with an inductance of 9 μH and a self-capacitance of 24 pF.

The diagram below is a prototype buck regulator. We apply a switching input A from a function generator. The input voltage is VS and the output is VL.


Figure: Buck Regulator Breadboard Circuit. We start with VL = 10 V and A is ±3 V with 8-μs period of which the voltage spends 1 μs at +3 V.

During each switching cycle of a buck regulator, the inductor goes through three phases. In the charging phase, the transistor switch is closed and the power supply charges the magnetic field of the inductor. The inductor voltage is positive and its current is increasing. The inductor charges the load capacitor. In the discharge phase, the transistor switch is open. The inductor voltage is negative and its current is decreasing. At first, the inductor continues to charge the load capacitor, but as the inductor current drops below the load current, the capacitor starts to discharge. In the harmonic phase, the inductor current is small but the voltage follows a damped harmonic oscillation the resonant frequency of the coil in parallel with its own parasitic capacitance, the diode capacitance, and the switching transistor output capacitance. During the harmonic phase, the capacitor discharges into the load. We see these three phases in the coil current trace below.


Figure: Coil Current with 1N914 Diode. Bottom trace is the buck regulator switching input, A, acting as the trigger, 1 μs/div. Top trace is the voltage across a 0.9-Ω resistor in series with the coil at the output end, 0.5 V/div. Zero current is the lower dashed line. The peak current is 1.1 V / 0.9 Ω = 1.2 A. Note the current does not drop below zero because the reverse recovery time of the 1N914 is only 4 ns with a reverse current of 10 mA.

We obtained the above traces with Q1 a ZTX690A and Q2 a ZTX790A. The charging phase does not begin until 200 ns after the rising edge of the A. The typical turn-on time of the ZTX690A is 33 ns and of the ZTX790A is 35 ns. The charging phase continues for 900 ns after the falling edge of A. The typical turn-off time of the ZTX690A is 1300 ns and of the ZTX790A is 600 ns. Decreasing R1 to 100 Ω and R2 to 200 Ω has little effect upon the transition delays in our circuit.

During the charging phase, the coil current increases to 1.2 A from zero. During the discharge phase, it decreases to 0.0 A. During the harmonic phase, the current is near zero. The above traces we obtained with a 1N914 diode. When we used the larger and slower 1N4001, we obtained the following trace, where the coil current becomes negative during the harmonic stage, during the reverse recovery phase of the diode.


Figure: Coil Current with 1N4001 Diode. Bottom trace is the buck regulator switching input, A, acting as the trigger, 1 μs/div. Top trace is the voltage across a 0.9-Ω resistor in series with the coil at the output end, 0.5 V/div. Zero current is the lower dashed line. The peak current is 0.96 V / 0.9 Ω = 1.1 A. Note the current dropping below zero because the reverse recovery time of the 1N4001 is 2 μs for reverse current of 1 A.

The trace below gives the voltage across the coil during one cycle. The buck regulator is in equilibrium, so the average coil current is constant. The increase in inductor current each cycle is proportional to the area under the coil voltage trace, so this area must be zero, and it appears to be so. The 1N914 capacitance is 4 pF, the ZTX790A collector capacitance is 24 pF, and the coil's parasitic capacitance is also 24 pF, so we expect the oscillations to be 7.3 MHz. We observe 6.0 MHz.


Figure: Coil Voltages. Bottom trace is the buck regulator switching input, A, acting as the trigger, 1 μs/div. Top trace is the voltage across the coil, 5 V/div, with zero being the center of the display.

The traces below show the load voltage and switching diode voltage, which are at the coil ends. The input voltage remains a constant 10 V, which we mark on the screen with the upper dashed line. During the charging phase, the voltage across Q1 is at first small, but increases to around 1 V as the current increases. We are dissipating heat in the transistor.


Figure: Coil Terminal Voltages. Bottom trace is the buck regulator switching input, A, acting as the trigger, 1 μs/div. Center trace is coil terminal connected to the switching transistor, 5 V/div with 0 V and 10 V marked by dashed lines. The power supply is 10 V. Top trace is load voltage, 1 V/div with 0 V marked by the upper of the two dashed lines.

A close look at the load voltage in the above figure shows that it is increasing during the charging phase, decreasing during the entire discharging phase, and remaining constant during the harmonic phase. Our load capacitor is a 22-μF tantalum bead. We replace it with a 20-μF ceramic capacitor. The load voltage ripple drops by a factor of three. We AC-couple the ripple and increase the gain to obtain the trace below.


Figure: Coil Terminal Voltages with 20-μF Ceramic Capacitor for C2. Bottom trace is the buck regulator switching input, A, acting as the trigger, 1 μs/div. Center trace is coil terminal connected to the switching transistor, 5 V/div with 0 V and 10 V marked by dashed lines. The power supply is 10 V. Top trace is the load voltage AC-coupled, 50 mV/div.

We now see the capacitor charging at 0.062 V/μs, which for a 20-μF capacitor implies a current of 1.2 A, which is correct. During the discharge phase we see the load voltage reach a peak and then start to drop. During the harmonic stage, the output capacitor is discharging at 0.025 V/μs or 500 mA.

Our average load voltage is 1.85 V. The load is a 5-Ω resistor, so we are delivering 370 mA and 680 mW. Meanwhile, we are drawing 150 mA from 10 V, so we are consuming 1.5 W. Our buck regulator is 46% efficient. Diode D1 carries an average of 600 mA for 3/8 of the time with forward voltage drop roughly 1.1 V, dissipating 250 mW. Transistor Q2 carries an average of 600 mA for 2/8 of the time with saturation voltage roughly 0.40 V, dissipating 60 mW. During switch-off, which takes Q2 around 200 ns, it conducts 1.2 A with an average of 5.0 V for 0.2/8 of the time, dissipating 150 mW. Resistor R1 carries 10 mA over 10 V for 1.7/8 of the time, for another 20 mW. The coil carries root mean square current 800 mA for 5/8 of the time with resistance 0.4 Ω, dissipating 160 mW. These losses together amount to 640 mW. Add this to the 680 mW deliver to the load and we still have 180 mW unaccounted for.

We change Q1 for a 2N4401, which has a faster switching time (turn-on 35 ns, turn-off 255 ns compared to 33 ns and 1300 ns for the ZTX690A). The delay between the rising edge of A and the turn on of Q2 decreases from 200 ns to 100 ns. The turn-off delay drops from 900 ns to 250 ns. The load voltage drops to 1.2 V and the supply current to 70 mA. Our efficiency is 41%. We switch Q2 for a 2N4403, but its current gain is only 20 at 500 mA, which is insufficient even when we drop R1 to 200 Ω. With Q2 as before, and the new Q1, we increase the switching frequency and obtain the following traces.


Figure: Coil Terminal Voltages with 2N4401 for Q1. Bottom trace is the buck regulator switching input, A, acting as the trigger, 1 μs/div. Center trace is coil terminal connected to the switching transistor, 5 V/div. Top trace is the load voltage AC-coupled, 50 mV/div. Power supply is 10 V.

We are drawing 150 mA from our 10-V supply and delivering 1.78 V to our load, so efficiency is 42%. Here are some ideas for increasing efficiency.

[13-MAY-14] We increase VS to 15 V. Input current is 140 mA and output voltage with 5-Ω load is 2.3 V. Efficiency is 50%. Turn-off time of Q2 is 200 ns with R2 1.0 kΩ and 500 ns with 470 Ω.

[15-MAY-14] We receive the SB140-E3/54 Schottky diode. We install it as D1. The voltage across the SB140 during the discharge phase is around 0.4 V. We reduce the switching frequency to around 50 kHz. We have 3.1 V on the 5-Ω load and we are drawing 203 mA from the 15-V supply. Efficiency is 56%. Turn-off of Q2 is 550 ns after the transition on A and 390 ns after turn-off of Q1. We switch Q2 to the ZTX949. We have 3.0 V on our load and we draw 220 mA. Efficiency is 55%. Turn-off is 820 ns from transition on A and 640 ns from turn-off of Q1.

We make various changes to the circuit and measure efficiency. Ceramic capacitors for C1 had no effect. Increasing the ceramic capacitor C2 had no effect. We are using the minimum pulse width provided by our function generator, 1/8 of the period. Longer pulse lengths decrease the efficiency.

Test Q1 R1
(Ω)
R2
(Ω)
R3
(Ω)
Q2 D1 R4
(Ω)
f
(kHz)
VS
(V)
PL
(W)
η
(%)
1 2N4401 1000 1000 120 ZTX790A SB140 5 63 15 1.37 61
2 2N4401 1000 1000 470 ZTX790A SB140 5 63 15 1.46 56
3 2N4401 1000 470 120 ZTX790A SB140 5 63 15 2.0 61
4 2N4401 1000 470 120 ZTX949 SB140 5 63 15 2.2 61
5 2N4401 1000 470 120 ZTX949 SB140 10 63 15 2.6 72
6 2N4401 1000 470 120 ZTX949 SB140 10 63 20 4.6 70
7 2N4401 1000 1000 120 ZTX949 SB140 10 63 20 2.9 64
8 2N4401 1000 1000 120 ZTX949 SB140 10 100 20 3.3 62
9 2N4401 1000 1000 120 ZTX949 SB140 10 50 20 3.4 72
Table: Efficiency of Buck Converter with Changes. Names of parts as shown here. Switching frequency is f. Pulse width 12.5%. Input voltage is VS. Output power is PL and efficiency is η. All circuits used the air-core inductor shown here.

[29-MAY-14] With 20 V, 62 kHz, R1 = 1 kΩ, R2 = 1 kΩ, R3 = 120 Ω, we are drawing 200 mA from the supply and delivering 2.7 W to our 10-Ω load. The coil terminal voltage and the switching signal are shown below.


Figure: Coil Terminal Voltages. The second division from the bottom is 0 V for all traces. Bottom trace is the buck regulator switching input, A, acting as the trigger, 2 μs/div. Center trace is coil terminal connected to the switching transistor, 5 V/div. Top trace is the load voltage, 1 V/div. The load voltage is 5.2 V.

The charging phase is 1.8 μs, discharge phase is 4.2 μs, harmonic phase is 9.6 μs. The transition from charging to discharging takes place in 200 ns, the transition from harmonic to charging takes 200 ns also. Adding these together, we get the entire 16 μs switching period. We estimate the following power losses.

  1. Dissipation occurs in Q2 during the charging phase. The emitter-collector voltage, VEC, increases linearly from V1 = 0.1 V to V2 = 0.5 V. Average current drawn from the 20-V supply is 200 mA, which is drawn entirely during the 1.8-μs charging phase. With constant voltage across the inductor, current increases linearly from 0.0 A to I = 3.6 A in τ = 1.8 μs. Integrating the power dissipation during the charging period, the heat loss is Iτ (V1/2 + (V2V1)/3) = 1.2 μJ, or 74 mW.
  2. At the end of the charging phase, VEC jumps from V1 = 0.5 V to V2 = 20.5 V in τ = 200 ns. The output capacitance of the transistor is about 110 pF and of the coil is 20 pF, so we expect of order 15 mA to flow out of this capacitance, which is insignificant compared to the coil current. As Q2 switches off, and until D1 starts conducting, I = 3.6 A is flowing through the transistor and into the coil. Loss in Q2 is Iτ (V1 + (V2V1)/2) = 7.6 μJ, or 470 mW.
  3. During the discharge phase, the current in L1 drops linearly from I = 3.6 A to 0.0 A. The voltage across D1 is starts at V1 = 0.5 V and ends at V2= 0.2 V. Loss in D1 during the τ = 4.2-μs discharge phase is Iτ (V1/2 - (V1V2)/3) = 2.3 mJ, or 140 mW.
  4. Dissipation in the 0.4-Ω resistance of the coil occurs for 2 μs during charging and 8 μs during discharge. Energy loss for charging time τ, resistance R, peak current I is E = I 2 τ R / 3. The same formula applies to the discharge phase when current drops linearly from I to zero. So we get 4 μJ loss during charging and 12 μJ during discharge, which is 1.0 W.
  5. Dissipation in R2 occurs for 2 μs during charging. We have 20 V across R2, so 0.4 W for 2 μs out of every 16 μs, which is 50 mW.

Adding these up we get an estimated loss of 1.7 W. Our observed loss is 1.3 W. Our calculations suggest that most of our loss is in the resistance of the coil.

[12-JUN-14] We wind the inductor shown below. The wire is copper, 1.65 mm in diameter (14 AWG copper with insulating paint). Its resistance should be 8.3 mΩ/m. The coil diameter is 28 mm and there are 40 turns, so we expect its resistance to be 0.03 Ω. Our meter says the resistance is less than 0.1 Ω.


Figure: Big Toroid. Wire is 14 AGW. Toroid radius 25 mm, coil radius 14 mm, 40 turns.

We expect the toroid inductance to be around 9 μH. We replace our original coil with this one. If our calculations of losses given above are correct, we should see efficiency improve. But it remains at 70%.

We try a 100-μH ferrite-core toroidal inductor for L1. We have 2N3904 in place of Q1, having destroyed our only 2N4401. With the higher inductance, we can reduce the switching frequency. We settle upon 16.7 kHz, with 10-μs on-time for A and 50-μs off-time. Supply voltage is 20.0 V with 140 mA, and output voltage is 4.9 V, so efficiency is 86%. Transistor Q2 is no longer hot. The only loss that is affected by reducing the switching frequency is the turn-off loss in Q2.

We resolve to try the following circuit as a way to cause Q2 to turn off more quickly, so we can use a higher switching frequency and a smaller air-core inductor.


Figure: Fast Turn-Off Circuit. As presented in Zetex's DN30 design note.

We use an inductor and a transistor to provide a short-lived low-impedance connection between the emitter and base of Q2. The Q2 turn-on base drive is now a current sink of 27 mA rather than a saturated transistor in series with a resistor.

The above circuit reduces the switch-off time of Q2 from 200 ns to 20 ns. We find that Q2 no longer heats up. With L1 = 10 μH and 140 kHz switching, we obtain efficiency 80% and it is the coil that warms up.


Figure: Fast Turn-Off of Q2. Using circuit presented in Zetex's DN30 design note. Bottom trace is A, 0.1 V/div, going from 3.3 V to 0 V. Top trace is the collector of Q2, 5 V/div.

JUN-14

[27-JUN-14] We receive air-core inductors from Nova Magnetics. The 10-μH is 24 mm in diameter and 11 mm high. The 100-μH is 38 mm in diameter and 13 mm high. We measure the inductance of our selection of coils by resonance with 1.0 kΩ series resistance and 1 nF parallel capacitance.


Figure: Measured Inductances.

[30-JUN-14] The circuit below is a prototype buck converter that obtains power from a LWDAQ root cable. A through-hole RJ-45-RS connector receives LWDAQ ±15 V power. We switch Q1 with a 3.3-V logic level referenced to 0 V. But the converter output is referenced to −15 V.


Figure: Prototype LWDAQ Buck Converter Circuit Diagram. The A input is 0-3.3 V logic, and turns on and off Q1. In the first version we had a Schottky diode, D2, in place of Q4.

The circuit uses surface-mount transistors, diodes, resistors, and capacitors. We allow for wire-connected inductors in place of L1 and a wire-connected load across the converter output. Michigan University tested a range of ferrite inductors and found the 74437346100 10-μH, 3-A surface-mount inductor to be effective in a strong magnetic field: its inductance is 6 μH in a 0.6-T field. We allow for this inductor to be loaded in place of L1 and L2.

We decouple the ±15 V power supplies individually with 100 μF made out of parallel P1206 capacitors. We suspect that this capacitance is great enough to bring down the ±15V power supplies at the end of a 100-m cable. We decouple the output to −15 V with another 100 μF.

JUL-14

[01-JUL-14] We look at the switch-on of Q2 with 0-3.3 V logic drive. The switch-on with R1 = 100 Ω we show below.


Figure: Turn-On of Q2 with R1 = 100 Ω. Using circuit presented in Zetex's DN30 design note. Bottom trace is A, 0.1 V/div, going from 0 V to 3.3 V. Top trace is the collector of Q2, 5 V/div.

With R1 = 50 Ω we have twice the base current for Q2 during turn-on. The turn-on time drops from 100 ns to 50 ns.


Figure: Turn-On of Q2 with R1 = 50 Ω. Using circuit presented in Zetex's DN30 design note. Bottom trace is A, 0.1 V/div, going from 0 V to 3.3 V. Top trace is the collector of Q2, 5 V/div.

The longer turn-on time has no effect upon the converter efficiency when the inductor current drops to zero during the discharge phase. Even if we eliminate the harmonic phase by increasing the switching frequency, we still see no significant improvement in efficiency as a result of the shorter turn-on.

[30-JUL-14] Yuxin has been working on the printed circuit board prototype for the past three weeks. The photograph below shows the state it's in today. The board obtains ±15 V power from a LWDAQ cable.


Figure: Buck Converter Prototype on A208001A Printed Circuit Board.

The components are as shown here, with the exception of D2, which we change to a 1N914 silicon diode, and in later versions, a silicon diode made out of a 2N3904 transistor. The purpose of D2 is to apply a charging voltage to L2 in the first few hundred nanoseconds after Q1 turns on. When we used a Schottky diode for D2, the charging voltage was reduced, so L2 took longer to charge, which increased the minimum on-time for Q1. With a silicon diode for D2, we can apply a shorter on-pulse and still get a fast turn-off.

The track lengths for component connections on this A208001A circuit board are too long for efficient switching. We added wire connections from the −15V capacitor bank and Q2 to D1. We find that an LXZ1-PR01 royal blue LED load over-heats, shorts, and damages the buck converter. We have three 1N4001 diodes in series, glued to a heat sink, as a load instead. We use a 10-μH ferrite-core surface mount inductor for L2 in the switch-off circuit. If we use 5.6 μH instead, the switch-off still works well. Given that this particular inductor has inductance 6 μH or higher for fields up to 0.6 T, we trust that our switch-off will work in fields up to 0.6 T.

At 100 kHz, we adjust the duty cycle of A so we get 1 A of load current when L1 = 10 μH. Now we drop L1 to 5.6 μH. We find Q2 starts to over-heat and the load current increases. At 100 kHz, the optimal duty cycle is 9.4%, which is roughly 1 μs of on-time. With 26 V across L1 = 10 μH, current will reach 2.6 A from a 0-A start. But with 5.6 μH, the current reaches 4.6 A. The transistor heats up and takes longer to turn off. The load current increases.

Yuxin made the coil shown above by winding wire onto a hand-made cardboard form. The coil is 30 mm in diameter and 9 mm high. By tank resonance, we measure its inductance to be 12 μH. The following graph shows the converter efficiency versus frequency, as well as duty cycle for 1-A load current. With forward current 1 A, the three 1N4001s in the load drop roughly 2.7 V.


Figure: Efficiency and Duty Cycle for One-Amp Load Current. We provide plots for two inductors, a hand-made, 12-μH air-core inductor, and a surface-mount, 5.6-μH ferrite-core inductor.

With the 12-μH air-core inductor, the harmonic switching phase vanishes at 150 kHz. Above this frequency, the inductor current is always greater than zero.

[31-JUL-14] Yuxin repeats the above measurements with a 5.6-μH ferrite-core inductor. The harmonic phase for the 5.6-μH inductor vanishes at 290 kHz. With the 5.6-μH and 10-μH ferrite-core inductors, we obtain the following graph of load current versus duty cycle at 300 kHz.


Figure: Load Current versus Duty Cycle at 300 kHz. The inductor L1 is either 5.6 μH or 10 μH ferrite-core. The load is three 1N4001 diodes in series with a resistor or either 0.1 Ω or 1.0 &Omage;.

If α is the duty cycle, a perfect buck regulator will give output voltage, VO = αVI, where VI is the input voltage. In our case, we have roughly 29 V input, 10% duty cycle, and 2.8 V output. When the load is a series of diodes and 0.1 Ω, its forward current increases rapidly with voltage.

The graph below compares the efficiency of a 74437346100 10-μH ferrite-core inductor to the 5.6-μH inductor in the same family.


Figure: Efficiency and Duty Cycle for One-Amp Load Current with Aluminum Heat Sink. We provide plots for 5.6-μH and 10-μH ferrite-core inductors.

The duty cycle for 1-A output current is constant with frequency above the point at which the harmonic phase vanishes.

AUG-14

[28-AUG-14] Yuxin tried a variety of PNP transistors with SOT-23 packages in place of Q2. The FMMT591, PBSS4041, ZXTP25040DFH, ZXTP2025F all appear from their data sheets to be suitable for high efficiency switching in our buck converter. The FMMT591 and PBSS4041 do not appear to be able to supply 3 A with the base current available from Q1. The ZXTP24040 works okay, but tends to get hot because it takes too long to turn off. The ZXTP2025F turns off quickly and supplies 3 A easily. All our best results we obtained with this transistor.

OCT-15

[05-OCT-15] We are concerned about the viability of PNP switching transistors in neutron radiation. We find that their current gain decreases dramatically. The threshold voltage of p-channel mosfets is immune to neutron radiation, but is affected linearly with ionizing radiation. We have already measured the ionizing tolerance of the NDS356AP mosfet. Its threshold voltage becomes more negative by 1 V after 2 kGy. We assemble the following circuit, in which Q2 is now an NDS356AP p-channel mosfet. We drive the gate with a resistive divider and supply 30V for VIN. The inductor 5.6 μH, ferrite-core 74437346056, with resistance 43 mΩ


Figure: Buck Converter Using NDS356AP P-Channel Mosfet for Switching.

On our printed circuit board, we implement the circuit below by connecting 0V and VEE together, loading the p-channel mosfet directly into the A2 footprint, and loading R2 and R4 onto available pads. We connect a 2-Ω resistor as a load, and adjust the duty cycle of our ±3 V control signal (A) so as to bring the converter output voltage to an average of 2 V.


Figure: NDS356AP Switching. Frequency 100 kHz, L1=5.6μH, duty cycle 5.6%, output 2.0 V, R1=100Ω, R2=220Ω, R3=2.0Ω, R4=1.0kΩ. Time scale 100 ns/div. Sharp square wave is ±3 V drive signal. The rounded square wave is the drain of Q2, 5V/div. The top trace is the gate of Q2, 5V/div.

The turn-off is slowed down by the falling drain charging the gate capacitance, which is being drained by R2. We see the gate sitting at 4 V below the source for 200 ns as the drain drops from +30 V to −3 V. The Q2 package is too hot to rest a finger on. Efficiency is 67%. The lowest switching frequency at which we can obtain a 2-V output is 20 kHz. At 10 kHz, the maximum output voltage we can obtain is 1.4 V for a duty cycle of 1.4%.


Figure: NDS356AP Switching. Frequency 10 kHz, L1=5.6μH, duty cycle 1.4%, output 1.4 V, R1=100Ω, R2=220Ω, R3=2.0Ω, R4=1.0kΩ. Time scale 200 ns/div. Sharp square wave is ±3 V drive signal. Rounded square wave is drain of Q2, 5V/div. The top trace is the gate of Q2, 5V/div.

We increase frequency from 20-300 kHz, adjusting the output voltage to 2.0 V by increasing the duty cycle. We obtain the following plots of efficiency and duty cycle versus frequency.


Figure: Efficiency and Duty Cycle with NDS356AP Switch and L1=5.6μH. Input 30 V, output 2.0 V, R1=100Ω, R2=220Ω, R3=2.0Ω, R4=1.0kΩ.

[07-OCT-15] We reduce R1, R2, and R4 by a factor of two, so as to accelerate the turn-off of Q2. We obtain the following trace at 100 kHz. The turn-off takes about 100 ns, when previously it took around 200 ns.


Figure: NDS356AP Switching. Frequency 100 kHz, L1 = 5.6μH, duty cycle 6.3%, output 2.0 V, R1 = 50Ω, R2 = 100Ω, R3 = 2.0Ω, R4 = 470Ω. Time scale 100 ns/div. Sharp square wave is ±3 V drive signal. The rounded square wave is the drain of Q2, 5V/div. The top trace is the gate of Q2, 5V/div.

With the turn-off taking half as long, the loss in Q2 during turn-off will be halved. In the plot above, we have 30 V across 10 μH for 500 ns. The initial current in Q2 is zero, because the converter is entering its harmonic state before switch-on. The current through Q2 ramps up to 30 × 0.5 μs / 5.6 μH = 2.7 A. The turn-off puts an average of 15 V across Q2 with current 2.7 A for 100 ns. At 100 kHz that's an average of 400 mW. While Q2 is on, its channel resistance will be at most 0.3 Ω with our gate-source voltage of −5 V. With peak current 2.7 A after 0.5 μs, we get 55 mW dissipated in Q2 while it is on. We have an peak 2.7 A in L1 during the charging and discharging phases, which last for 7.5 μs of the 10-μs period. The inductor's resistance is 43 mΩ, so we have resistive loss 120 mW. The voltage across the diode is 0.6 V for 7.0 μs with average current 1.4 A, which dissipates 570 mW. The shorter turn-off comes at the cost of an increase in the current through Q1 while Q2 is turned on. Previously we had 23 mA flowing, for 0.69 W in R2, R4, Q1, and R1. Now we have 46 mA and 1.4 W. At a 6.3% duty cycle, however, this 1.4 W amounts to 90 mW. Adding the losses up we come to an estimate of 400 + 55 + 120 + 570 + 90 = 1200 mW. What we observe is 3 W in and 2 W out to the load, so our actual loss is 1.0 W. We obtain the following graph of efficiency and duty cycle versus frequency.


Figure: Efficiency and Duty Cycle with NDS356AP Switch and L1=5.6μH. Input 30 V, output 2.0 V, R1=50Ω, R2=100Ω, R3=2.0Ω, R4=470Ω.

Despite the faster turn-off time, the maximum efficiency remains 67%. But we can operate at slightly higher frequencies.

[08-OCT-15] We replace the 5.6-μH inductor with 10 μH. With the larger inductor, the converter no longer enters a harmonic phase during the switching cycle at 100 kHz.


Figure: Efficiency and Duty Cycle with NDS356AP Switch and L1=10μH. Input 30 V, output 2.0 V, R1=50Ω, R2=100Ω, R3=2.0Ω, R4=470Ω.

We set the frequency to 150 kHz and duty cycle to 7.5%. If our inductor were 5.6 μH we would see 2.0 V out and 67% efficiency. With 10 μH we see 1.8 V out. Input current is 86 mA for efficiency 63%. Michigan University measured the inductance of our 10-μH part in increasing magnetic fields and obtained the following results.


Figure: Inductance versus Magnetic Field for 10-μA 74437346100 Inductor. Data from Ryan Edgar, Michigan University, 2014.

The maximum field we expect in the New Small Wheel is 0.6 T. Our p-channel mosfet buck converter, equipped with this 10-μH inductor, would produce 1.8 V in a 0.0-T field, and 2.0 V in 0.7 T.

We assemble the circuit shown below. We supply the circuit with 30-V power. The output capacitor is only 22 μF. The load is a LuxeonZ deep-red LED LXZ1-PA01 and a 0.1-Ω resistor.


Figure: Buck Converter Using NDS356AP and LuxeonZ Load.

We use the voltage across the resistor to measure the output current. With L1 = 10 μH and switching frequency 150 kHz we set duty cycle to 8.7%. Load current is 800 mA, voltage 2.2 V, and 30-V input current 86 mA for efficiency 68%. After ten minutes, the LED hot. Current is 930 mA, output voltage 2.2 V, input current 98 mA for efficiency 70%. We obtain the following plots of initial load current versus duty cycle for 10 μH and 5.6 μH inductors.


Figure: Load Current versus Duty Cycle at 150 kHz. The inductor L1 is either 5.6 μH or 10 μH ferrite-core. We measure load current three seconds after turn-on.

We set duty cycle to 7.5% and turn on with L1 = 5.6 μH. Current starts at 1000 mA and after five minutes is stable at 1050 mA. Components LED1 and Q2 are almost too hot to touch. We set L1 = 10μH. Initial current is 600 mA. After five minutes, current is stable at 605 mA with 30-V input current 63 mA. We try 200 kHz and 8.5% and get initial current 740 mA, settling to 830 mA with input current 91 mA. With L1 = 5.6 μA initial current is 1020 mA, settling to 1080 mA with input current 125 mA and 65% conversion efficiency.


Figure: Cost of One Buck Converter. Assume shared C1 between 36.

We propose to build one such buck converter for each of 36 LEDs in our contact injector. If we share the input capacitor, C1, between all 36, the component cost per converter is $3.04, half of which is the inductor. The LED is another $1.50. We turn on each LED by applying a switching signal to Q1 of its converter. We can install over-current protection on VIN, which will therefore be shared by all converters.

With 5.6 μH and 1000 mA flowing through the LED, we short the LED terminals with tweezers. In less than a second, Q2 is smoking. It fails as a short-circuit, and remains a short circuit even when we remove the switching signal from Q2. If we have 36 such converters in parallel, and one Q2 fails in this way, the entire circuit fails.

DEC-15

[03-DEC-15] We obtain the following plots of load current versus switching duty cycle for three inductor values. The load is a Luxeon Z deep-red LED LXZ1-PA01.


Figure: Load Current versus Duty Cycle. Switching frequency 150 kHz. Load LXZ1-PA01.

We propose to set the duty cycle to a fixed 7.5%, load the 10-μ inductor. The nominal deep-red LED current will be 600 mA. In a 0.6-T field, this current will rise to 1000 mA, which our LED can tolerate when loaded into a good heat sink.

MAR-16

[17-MAR-16] We propose the following buck converter prototype for use in the New Small Wheel. The circuit is designed to plug directly into the LWDAQ, with 1 μF decoupling capacitors on they ±15 V power supplies, as opposed to the 100 μF we have been using. At 150 kHz and 7.5% duty cycle, the peak current is 1.5 A into the inductor and we expect a drop of only 0.5 V across each capacitor.


Figure: Buck Converter Prototype.

We add a fuse that we hope will blow when we have a short circuit on the output or an overheat of the switching mosfet, or a failure of the switching logic signal. Instead of an NPN transistor in place of Q1, we now use an N-channel mosfet two switch the gate of Q1, and we can apply a 3.3 V logic level directly to this gate. The plan is to have one such buck converter for each LED in a 36-LED Contact Injector, and turn on each LED by applying a 150 kHz 7.5% duty cycle switching signal to S. Otherwise, S is held at zero.

JUN-16

[05-JUN-16] WE build the above prototype. With 7.5% duty cycle the LED voltage is 2.1 V and current is 790 mA. Input voltage is 30 V and 85 mA. Efficiency is 65%.

JUL-16

[07-JUL-16] We note that the LWDAQ power supplies are dropping by roughly 1 V during the charging phase of our switching cycle.


Figure: +15-V Power Supply While Switching. The lower trace is S. The upper trace is +15 V, 2 V/div. For the −15-V power supply see here.

On the driver, there is a 0.47-Ω resistor in series with both the +15-V and −15-V power supplies. With a 10-μH inductor, 150-kHz switching frequency, and 7.5% duty cycle, the charging phase lasts 500 ns, during which time the inductor current reaches 1.5 A. This current, passing through the 0.47-Ω resistors, drops 0.7 V. We insert a resistor R in series with +15-V and −15-V. We consider decoupling capacitors C for both supplies, with the inductor connected directly across these capacitors with a switch. We solve for the voltage across the capacitors when we close the switch after it has been open for a long time. You will find our solution here: Page_1, Page_2, Page_3.

With a 130-m root cable, R will contain roughly 10 Ω of wire resistance, 0.47 Ω on the driver itself, and whatever value we load on the buck converter. Suppose we load 10 Ω on the converter and start with a short cable. We let C be 10 μF and L is 10 μH. The frequency of the harmonic generated by the capacitor and the inductor will be 22 kHz. During the 500-ns charging phase, we expect the capacitor voltage to drop by aroun 40 mV. With the current at 1.5 A, the capacitor voltage is dropping at 0.15 V/μs. The average current is around 60 mA, which drops 0.6 V across R. During the charging phase, this drop increases to 0.64 V. The LWDAQ power supply will see a 4 mV drop during the charging phase.

OCT-16

[06-OCT-16] We complete the schematic for a 36-Way Contact Injector (A2080A). The circuit uses the same bipolar transistor regulators and power switches we developed and tested for the Bar Head (A2082), as well as the LVDS transceiver. We add 1-kΩ resistors R11 and R12 across the power switches (see S2080_1). These resistors charge the 20-μF ±15-V decoupling capacitors when we plug power into the circuit. The capacitors are charged within 100 ms. When we assert WAKE, the transistor switches connect the decoupling capacitors directly to the LWDAQ cable through R12 and R13, 10-Ω decoupling resistors.

The 20-μF decoupling capacitors are each made of 10 separate 2.2-μF 100-V P1206 ceramic capacitors, C3216X7S2A225M160AB by TDK (see S2080_2. With 15-V bias, these capacitors lose 10% of their 0-V capacitance, so the total decoupling capacitance is around 20 μF for ten of them. The 10-Ω resistors isolate the LWDAQ cable from the current pulses drawn by the A2080's buck converters (see S2080_3).

The buck converters draw power during 500-ns pulses occuring at 150 kHz. During a pulse, the inductor current increases at 3 A/μs for our 10-μH inductor in no ambient magnetic field, or 5 A/μs for the same inducor in a 0.6-T ambient field. At the end of the 500 ns, the current can reach 2.5 A. At 2.5 A, the voltage on an ideal 20-μF capacitor drops at 0.12 V/μs. The current pulses seen by the LWDAQ cable should be of order 0.1 V ÷ 10 Ω = 10 mA. The LWDAQ Driver has 0.47-Ω resistors in series with its ±15-V power supplies, so we expect to see 150-kHz noise no greater than 5 mV at the LWDAQ Driver.

The average current drawn by the buck converter in a 0.6-T field is around 110 mA when we maintain 500-ns pulses at 150 kHz. The efficiency of the buck converter is 65%, input voltage is 28 V, output voltage is 2.1 V with LED current 1000 mA. The 30-V power is reduced to 28 V by the drop in the two 10-Ω resistors. The loss in the resistors is 0.2 W, which drops the total efficiency to 61%.

Once we have a printed circuit board, LWDAQ transceiver, logic chip, and enclosure, the additional cost per injector is the cost of assembling the components in this circuit.


Figure: Cost of One Injector. Assembly cost for one additional part is roughly $0.30. Costs are in 1000's quantity for all parts.

The additional cost of making a 40-way injector circuit instead of a 36-way injector circuit is around $8, not counting the extension of the face plate with hole in it for the ferrules.

DEC-16

[01-DEC-16] We have submitted the A208001D 36-way Contact Injector circuit board for fabrication. We have received three new types of 10-μH inductor in packages almost identical to the 74437346100, having discovered that the 7443734610 is out of stock with delivery time fourteen weeks.

Part Number Length (mm) Width (mm) Height (mm) Core
74437346100 7.4 6.8 2.9 iron powder
SRP7028A-100M 7.5 6.8 2.9 carbonyl powder
HCMA0703-100-R 7.3 6.8 2.8 iron powder
FDSD0630-H-100M=P3 7.0 6.7 2.7 metal
Table: Candidate Inductors for Contact Injector Buck Converters. Dimensions measured from samples. Length includes the two mounting pads. Core material from Digi-Key description of the part.

Carbonyl powder is a 99.5% pure iron powder. We are not sure what "metal" is, so we cut open the FDSD0630 inductor and find that its body is entirely made of a sintered metallic powder, which we assume to be iron. To the first approximation, all four inductors have the same powdered iron core.

[19-DEC-16] We partially-assemble our first A3030A and prepare firmware P2080A01 to provide 150 kHz switching with 7% duty cycle to all thirty-six buck converters. But we populate only numbers 1, 18, 23, and 36, one example of each corner of the sets of four in which the converters are arranged. We load a different inductor in each converter. We turn on the LEDs measure current consumption, current delivered, and efficiency assuming a 30-V power supply and measuring the voltage across the LED.

Part Number Converter ±15V (mA) LED (mA) Efficiency (%)
74437346100 1 84.6 740 64
HCMA0703-100-R 18 78.6 720 67
SRP7028A-100M 23 78.4 710 66
FDSD0630-H-100M=P3 36 76.7 710 68
Table: Comparison of Buck Converters with Different Inductors.

When the board is asleep, it consumes 0.5 mA from +15V, 5.1 mA from +5V and 0.0 mA from −15V. When awake, but with no LED turned on, current consumption is 6.0 mA from +15V, 5.1 mA from +5V and 3.1 mA from −15 V. The +5V current consists of 1.1 mA through R1, 0.9 mA through R2, 0.8 mA through R4, and a typical 1.7 mA supply to U1 (SN65LVDM180). Those add to 4.5 mA. The current consumption of U1 may be higher than typical because our power supply is 3.5 V rather than 3.3 V.

[21-DEC-16] We turn converter No18 on and measure S18 on Q181-3, G on Q181-1, and X on Q182-1, see S2080_3. Oscilloscope traces shown below.


Figure: Switching Signals at 720 mA LED Current. Trace 3 is 5 V/div logic pulse on gate of Q181. Trace 2 is G on drain of Q181, 5 V/div, center is 0V. Trace 1 is X on drain of Q182, 5 V/div, center is 0 V.

The buck converter has a charging and discharging phase, but no harmonic phase. The current through the inductor never drops to zero. The +15-V power supply average value is 14.2 V. The ripple is 60 mV. The average voltage at Q5-1 is 14.9 V and ripple is 9 mV. Between the two is R13, 10 Ω (see S2080_1), suggesting buck converter input current 70 mA. The average value of −15 V is −14.2 V and ripple is 40 mV, similar to the ripple on +15 V, but inverted. Average value at Q4-1 is −14.9 with ripple 5 mV.


Figure: Power Supply Ripple at 720 mA LED Current. Trace 3 is 5 V/div logic pulse on gate of Q181. Trace 2 is +15 V, AC-coupled 20 mV/div. Trace 1 is X on drain of Q182, 5 V/div, center is 0 V, showing no harmonic phase.

We replace R12 and R13 with 1.0 Ω (previously 10 Ω). We look at the ripple on either side of R13.


Figure: Power Supply Ripple at 720 mA LED Current. Trace 3 is 5 V/div logic pulse on gate of Q181. Trace 2 is +15 V, AC-coupled 20 mV/div AC-coupled showing 80 mV ripple. Trace 1 is Q5-1 20 mV/div AC-coupled showing 30 mV ripple.

Ripple on +15V at the LWDAQ Driver (A2071E) is 7 mV and on −15V is 5 mV. The driver and the A2080A are connected by a 7-m cable. We measure 825 mA current into the LED and 2.23 V across the LED and R181 for 1.8 W delivered to the load. According to the LWDAQ power supply monitors, the current delivered on +15 V is 92.0 mA and on −15 V is 85.1 mA. According to the average voltage across R13 and R12 these currents are 89.3 mA and 89.8 mA respectively. Assuming an exact ±15 V in the LWDAQ Driver, both measurements give us 68% efficiency in the buck converter.

We reduce the duty cycle of our switching signal from 7% to 0.6%. Each pulse is 40-ns long in a period of 6.5 μs.


Figure: Harmonic Phase for Low Duty Cycle. Trace 3 is 5 V/div logic pulse on gate of Q181, duty cycle 0.6%. Trace 1 is Q181-1 5 V/div showing harmonic oscillation with damping time constant of order 5 μs.

The P2080A01 firmware allows us to drive a single LED at full or medium power, and all LEDs simultaneously at low power. The current in LED No18 immediately after turning on is roughly 800 mA at full power, 580 mA at medium power, and 40 mA in low power. We have four LEDs loaded on our prototype and ±15V current is 30 mA when all four are running at low power. We expect 300 mA to turn on all thirty-six LEDs at low power, allowing us to see if all are operational at one time.

[22-DEC-16] Commands sent to the A2080A with firmware P2080A01 produce the following effects.

Command
(Hex)
LEDs On LED Current
(mA)
Converter Current
(mA for all)
Comment
0000 None 0 0 Asleep, ±15V connected through R10 = R11 = 1 kΩ
0080 None 0 0 Awake, ±15V connected through R12 = R13 = 1 Ω
0181 No1 900 86 No1, deep red, full power.
0182 No1 600 64 No1, deep red, medium power.
0182 No1 660 84 No1, green, high power.
XX83 All 40 220 All 36 deep red, low power, calculated from 24 mA for 4 LEDs.
1282 No18 800 85 No18, deep red, high power.
1782 No23 830 83 No18, deep red, high power.
1782 No23 610 81 No18, cool white, high power.
2482 No36 830 82 No36, deep red, high power.
Table: Effect of Command Words on A2080A with P2080A01 Firmware. An X is "don't care". The LED currents we measure for our prototype board. The converter current is the current flowing into the buck converters from ±15V, and does not include the ±15V current drawn when the board is awake but not driving any converter.

In the case of the green LED in location No18, the full-power current is 660 mA with forward voltage 2.76 V for efficiency 72%. The cool white in No23 has current 610 mA and forward voltage drop 2.97 V for efficiency 74%.

2017

JAN-17

[17-JAN-17] We have two pot magnets from Radial Magnet Inc., part number A32 made out of N35 neodymium. This material generates a surface field of roughly 1.2 T. The field is strongest in an annulus 3 mm thick on the underside of the magnet. We place this field on L011. The magnet sticks to the inductor.

Configuration+15V Input (mA)Comment
All lamps off, awake0Baseline current.
No1 full power, no magnet90Stays on indefinitely.
No1 full power, with magnet220Fuse blows after one second.
No1 2/3 power, no magnet63Stays on indefinitely.
No1 2/3 power, with magnet160Fuse blows after a few seconds.
All 4 at 0.7% power, no magnet6All four at low power.
All 4 at 0.7% power, magnet on No114No1 gets brighter.
Table: Effect of Adhering 1.2-T Pot Magnet to L011 Shield.

When we apply the magnet to L011, the current through the deep-red No1 LED increases. At 0.7% power, the increase is 6 to 14 mA, at 67% it is 63 to 160 mA, at 100% it is 90 to 220 mA, which is a factor of 2.3, 2.5, and 2.4. It appears that the effective inductance of L011 drops by a factor of 2.4 in 1.2 T, resulting in an increase by the same factor in the peak current reached during the charging period. The effective inductance is now 4.2 μH instead of 10 μH. We are unceratin of the magnetic field strength, but have asked the manufacturer of the magnet for a field map. The L011 inductor is 74437346100, the magnet tested by University of Michigan at 0.6 T, at which field it had an effective inductance of 5.6 μH.

[18-JAN-17] We have seven 13-mm diameter, 3.2-mm thick N35 disk magnets, part number 8022 from Radial Magnet Inc.. At K&J Magnetics we find a field-mapping calculator for such magnets, and obtain the following for a single disk and for seven disks in a row.


Figure: Field Maps for N35 Disk Magnets. Legend is in Gauss, where 1 Tesla = 10,000 Gauss.

The field is stronger at the perimeter of the end face than at the center. In the case of one disk, the field at the center of the end face is 0.30 T and at the perimiter is closer to 0.5 T. For seven disks, the field at the center is 0.63 T and at the edge is closer to 0.7 T. When we stick the magnets to our inductor L011, the pull force is stronger when we place the perimiter of the magnet over the center of the inductor. We measure the additional current consumption that results from turning on LED No1 to 2/3 power for various arrangements of magnets.


Figure: Input Current versus Field Strength. The LED is being driven at 2/3 power. Side-strength field is ±0.1 T, center strength is ±0.2 T at the inductor.

It appears that the current doubles for a field of 0.7 T, which suggests the effective inductance of L011 has dropped to 5 μH from 10 μH.

FEB-17

[06-FEB-17] We assemble a fiber-mounting plate onto a circuit board with thirty-six LEDs. Most are red, but some are green, blue, white, and yellow. We fit a fiber tip into one of the mounting holds. It is roughly 1 mm from the LED, and the LEDs are centered to ±0.5 mm. We turn on to full power and measure power at the other end of the optical fiber. For six red LEDs we 42-50 μW. With a white LED the photodiode current is 16 μA, which suggests a total power of around 70 μW.

[15-FEB-17] We use an SD445 photodiode and 1% neutral density filter to measure the power emitted by LED No36 on our December prototype. We have firmware P2080A03, which supports ten power levels.


Figure: Power and Current versus Power Level. The power levels we transmit to the board with LWDAQ commands 2480 to 248A.

At 1.4 A diode current, the voltage across the diode and sensing resistor is 2.25 V and current drawn from the ±15 V supply for the converter is 174 mA. The voltage delivered to the converter is 29.5 V. The converter efficiency is 61%. The diode emits 620 mW of light while consuming 2.9 W of electrical power, for an optical efficiency of 21%.

[16-FEB-17] We note that the −15 V decoupling capacitors C18-C27 do not discharge after we unplug the circuit board from the LWDAQ, while the +15 V capacitors C8-C17 discharge in less than a second. The +15 V capacitor is a total of 22 μF discharging through R3 of 22 kΩ for a time constant of 500 ms. With all buck converters off, the −15 V capacitor discharges through the leakage current of thirty-six mosfets and diodes. We see the voltage drop to 13 V in roughly 100 s, suggesting a total leakage current of around 500 nA. We add R14, 22 kΩ from −15 V at its input to 0 V.

MAR-17

[30-MAR-17] We have a permanent magnet that generates a field of 450 mT in a cylindrical volume 25-mm long and 25-mm in diameter. We place the buck converter inductor in this field at power level 7. The fuse blows immediately when we have FDSD0630-H-100M in place of Ln1, but not for the other three inductors. We measure total LWDAQ +15-V current versus time for the other three inductors in 0 mT and 450 mT.


Figure: +15V Current versus Time for 0 mT Field, Various Inductors.

The 74437346100 blows the fuse after 200 s in no magnetic field. We have no heat sink attached to the A2080A circuit board.


Figure: +15V Current versus Time for 450 mT Field, Various Inductors.

The SRP7028A-100M current after 30 s is 170 mA with 0 mT and 180 mA with 450 mT, which suggests that its inductance has decreased by less than 10%, because we have already established that the buck converter current increases in approximate inverse proportion to the inductance. The HCMA0703-100-R performs well also, but its current increases from 175 mA to 210 mA.

APR-17

[03-APR-17] When we send a command of the form xxB0 to the A2080A, its current consumption, as measured by the Diagnostic Instrument, increases as high as 1000 mA.


Figure: +15V Current Measured by LWDAQ with Transmission of xxB0 to A2080A with Firmware P2080A03.abl.

We find a vulnerability in firmware P2080A03.abl. When we send a command with power level zero following a command for which the power level is not zero, there is a chance that a switching signal for one of the buck converters will be stuck hi, causing the LED to flash and the LWDAQ power supplies to be brought down. We fix this vulnerability in P2080A04.abl.